The slope of the line is therefore 60/80 (change in y over the change in x). To apply this slope (in order to extend the line from B), apply these changes to B at (100,100). Our new point A will be (100+80, 100+60) = (180,160).
The same strategy may be applied to find a new point for C. Compare C(50,160) to the vertex B(100,100). x increased by 50, but y decreased by 60. The new co-ords for C will be (100+50, 100-60), that is, C'(150,40).