CAN LIGHT ESCAPE FROM THE SUN? Not in my ill-conceived and erroneous calculation: [1]Chandrasekhar, "An Introduction To the Study Of Stellar Structure" p487 MASS of Sun = 1.985 x 10**33 gm [2]Abell, "Exploration of the Universe" p704 RADIUS of Sun = 6.960 * 10**10 cm [3]Bate, Mueller and White "Fundamentals of Astrodynamics" p35 ESCAPE SPEED = (2GM/r)**(1/2) p4 G = 6.670 x 10**-8 dyne cm x cm/ (gm x gm) [4]Sears, Zemansky "University Physics" Part 1 p662 c = 3 x 10 ** 4 m/sec [5]Sears, Zemansky "University Physics" Part 1 p80 dyne = gm * cm / (sec * sec) p462 dyne = 2.247*10-6 lb. Q: WHEN IS THE ESCAPE SPEED EQUAL TO c (THE SPEED OF LIGHT) A: ESCAPE SPEED = (2GM/r)**(1/2) [3] c**2 = 2GM / distance from star center distance from star center when speed of light escapes = (2GM) / c**2 = 2 * 6.667 * 10**-8 sec*sec*dyne*cm*cm * M / [3] (9 * 10**8) m*m gm*gm [4] = 2 * 6.667 * 10**-8 sec*sec*dyne*cm*cm * M / (9 * 10**8) m*m gm*gm * 10*4 cm/m * cm/m = 2 * 6.667 * 10**-8 sec*sec*(gm*cm/sec/sec)*cm*cm * M / (9 * 10**12) cm*cm gm*gm [5] = 2 * 6.667 cm * M / (9 * 10**20) gm = 1.48 * 10**-20 cm/gm * M = 1.48 * 10**-20 cm/gm * 1.985 * 10**33 Sun g [1] = 2.940 * 10**13 cm (for one Sun mass ) Sun radius = 6.960 * 10**10 cm [2] distance / Sun radius ratio = 422 times number of Sun Masses distance of lost horizon = 422 * k sun mass(es) * radius of sun in cm = 422 * Ksuns * Rsun cm Since I believe light does escape from the sun, k = 1 can't be true or we would not see the sun. The high density (mass per volume) of the neutron star must be considered along with all the relativistic effects.