- vavg = 65.0km/h
t = 2.5h
d = ?km
vavg = d/t
65.0 = d ÷ 2.5
d = 65.0 X 2.5
d = 162.5
The distance traveled is 163 km
- vavg = ? m/s
v1 = 3.44 m/s
v2 = 12.7 m/s
vavg = (v1 + v2)/2
vavg = (3.44 + 12.7)/2
= 8.07
The average velocity or speed is 8.07 m/s. Note the number of digits
- v1 = 9.5 m/s
v2 = 2.2 m/s
t = 3.6 s
a = ? m/s2
v2 = v1 + at
2.2 = 9.5 + 3.6a
a = (2.2 - 9.5)/3.6
a = -2.02777 watch the negative sign in this problem.
The acceleration is -2.0 m/s2 or the ball slows down at a rate of 2.0 m/s2
- v1 = 15.6 m/s
a = 2.1 m/s2
t = 5.3 s
v2 ? m/s
v2 = v1 + at
? = 15.6 + 2.1 x 5.3
= 15.6 + 11.13
= 26.73
The final velocity is 27 m/s
- a = 9.8 m/s2
t = 2.7s
d = ? m
v1 = 0.0 m/s (the object is dropped not thrown)
d = v1t + ½at2
d = 0.0 x 2.7 + ½ 9.8 x (2.7)2
= 0.0 + 35.721
The distance the object falls or height of the building is 35.7 m
- v2 = ? m/s
v1 = 3.22 m/s
a = 2.56 m/s2
d = 12.8 m
v22 = v12 + 2ad
v22 = (3.22)2 + 2 x 2.56 x 12.8
= 10.368 + 65.536
= 75.904
Now take the square root
v2 = 8.7122
The final velocity is 8.71 m/s