P&H 8.1
Each transaction requires 50,000 instructions and 5 I/O operations. The CPU can handle transactions at a maximum rate of 50M/50K, or 1000 transactions/second. The I/O limit for system A is 200 TPS and system B is 150 TPS. Thus the answer comes out simply as 200 and 150 since they are the limiting rates.P&H 8.5
100/(3*10^8*.5) = .67us or microseconds and 5000*10^3(3*10^8*.5) = .034 secondsP&H 8.8
Controller Overhead = 2 ms
Average Seek Time = 8 ms
Average Rotational Latency = (1 s/ 120 rotations) * 0.5 = 4.2 ms
Transfer Time (for one Read or Write) = 4000 B / 20000000 B/s = 0.2 ms
Read Time = Write Time = (2 + 8 + 4.2 + 0.2) ms = 14.4 ms
Processing Time = 20 M instrs / 400 MHz = 50 ms
Total Time per block = 2 * 14.4 ms + 50 ms = 78.8 ms
Speed of System = 1 block / 0.0788 sec = 12.7 blocks/second